[e^(i*pi)] + 1 = me (kvschwartz) wrote in princetonians,
[e^(i*pi)] + 1 = me
kvschwartz
princetonians

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lost email password

OK, I admit that this post very well make people wonder how I got into Princeton in the first place. However, I didn't know where else to ask.

I pretty much never use my Princeton email address. So I've forgotten my password.

Does anyone here know how I can get my password, or have it changed? Many thanks.

Feeling stoopid,

Kevin
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